Homework 2 — Diffusion, Mass Action & Membrane Potential

Problem 1: irreversible bimolecular kinetics with conservation of mass. Problem 2: coupled diffusion + reaction with product feedback inhibition. Problem 3: resting membrane potential by the chord-conductance (weighted Nernst) equation and why IV potassium is lethal.  ← back to index

Problem 1 — A + B → X + Y (irreversible, mass action)

With a = a₀−x and b = b₀−x (conservation of mass), the correct model is dx/dt = k(a₀−x)(b₀−x) = 2(10.5−x)(6.5−x) — statement (a) is TRUE, statement (b) is FALSE (y is a product, not a reactant), and “A depletes first” is FALSE: B is limiting (6.5 < 10.5 µg/ml), so B → 0 while A levels off at a₀−b₀ = 4 µg/ml. Curve shown is the exact analytic solution; markers are the numerical (Euler) solution as built in Simulink.

Problem 2 — Diffusion + X + Y → Z with product feedback inhibition

Dynamical system:  dx/dt = kx(x₀e − x) − k₁xy,   dy/dt = ky(y₀e − y) − k₁xy,   dz/dt = k₁xy − δz,   with   k₁ = max(0, α − γz). X and Y diffuse in from the ECF (kx=2, ky=3 /s; x₀e=10, y₀e=6 µg/mg); Z is consumed (δ=2/s) and inhibits its own production (α=10, γ=2).

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z at steady state (µg/mg)
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final k₁ (does NOT reach 0)
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x steady state
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y steady state

Answer to the assignment’s question: the reaction does not stop — it reaches a steady state where production of Z exactly balances its consumption, and k₁ settles at a positive value (α − γzss > 0).

Problem 3 — Resting membrane potential vs extracellular K⁺ (chord conductance)

Vm = (gNa/gtot)ENa + (gK/gtot)EK with gNa:gtot = 0.1, gK:gtot = 0.9, and Eion = 61.5 log₁₀([out]/[in]) mV at 37 °C. Baseline: Na⁺ 14 in / 140 out, K⁺ 140 in / 4 out → Vm = −79.3 mV (matches the measured value given). Drag the slider to add KCl to the ECF.

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EK (mV)
+61.5
ENa (mV)
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Vm (mV)
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excitability state

Why IV KCl is lethal: raising [K⁺]o to 29 mM depolarizes Vm from −79 mV to about −32 mV — far above the ≈−55 mV threshold. Neurons and cardiac muscle fire once, then their Na⁺ channels remain inactivated (h gates closed) at the depolarized potential, so no further action potentials are possible: the heart stops in diastole. This connects directly to the hyperkalemia experiment in Homework 4.